Question

Answer and readable solution please

A Mechanic Exerts a 20N force at the end of a 0.20m wrench. If this makes an angle of 60° with the handle, what is the torque produced on the nut.

Answer 1

The force applied by the mechanic will have two components the horizontal component Fcos60 alng the wrench and the vertical component Fsin60 perpendicular to the wrench. Now, the horizontal component acting along the wrench is unable to produce any torque as it is directed towards the nut(radial force).Whereas the vertical component is 0.2m away from the nut and can produce torque, equal to forcee times distance,

torque=Force * perpendicular distance between force and required torque(in case of radial force, this is zero)

=Fsin60 *0.2=20*sin60*0.2=17.32*0.2=3.464 Nm