Question

A uniform rod of mass M = 20 kg and length L = 5m is bent...

A uniform rod of mass M = 20 kg and length L = 5m is bent into a semicircle. What is the gravitational force exerted by the rod on a point mass m = 0.1 kg located at the center of the circular arc?

Please show all work and step by step, thank you!

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Answer #1

Substitute the values,

F = 2*6.67*10-11*0.1*20/52

= 3.353*10-11 N.

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