1)A star with the mass (M=2.0
Part A
.
initial ang mom = final ang mom
.
mom of inertia * ang speed = mom of inertia * ang speed
.
(2/5) m R2 * 2? / T = (2/5)m r2 * 2? / t
.
R2 t / T = r2
.
r = 3.5 x 108 * (0.200 /29*86400)1/2 = 98884 meters = 98.88 km is theradius
.
Part B
.
speed = distance /time = 2?r / t = 2? * 98884 /0.200 = 3.106 x 106 m/s
Get Answers For Free
Most questions answered within 1 hours.