Question

Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS​=42000 km.

Consider the mechanical energy of the same body on Earth at the South pole, at re​=6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.)

G = 6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97×1024 kg

What is the difference in the mechanical energy per kilogram between the two?

E =E= ___MJ.kg−1 (to two significant figures, don't use scientific notation)

(Part 2)

Consider the mechanical energy of a body at rest on the ground at the Earth's equator, at r_e = 6400\text{ km}re​=6400 km

Consider the mechanical energy of the same body at rest on the ground at the South pole, at r_e = 6400\text{ km}re​=6400 km. For this problem, we consider the Earth to be spherical.

(Remember, the object at the equator traces a circular path, the object at the Pole does not.)

G=6.67×10−11 Nm2kg−2, and the mass of the Earth is M=5.97×1024 kg

1. How much more mechanical energy per kilogram does an object on the ground at the Equator than on the ground at the Pole?
2. E= ___  MJ.kg−1. (2 sig figs, do not use scientific notation)

NOTE: IN PART B 31MJ is not the correct answer

Answer 1