A ball of mass 0.484 kg moving east (+xdirection) with a speed of 3.76 m/s collides head-on with a 0.242 kg ball at rest. Assume that the collision is perfectly elastic. A)What is be the speed of the 0.484-kg ball after the collision? B)What is be the direction of the velocity of the 0.484-kg ball after the collision? C)What is the speed of the 0.242-kg ball after the collision? D)What is the direction of the velocity of 0.242-kg ball after the collision?
let the final velocity of 0.484 Kg ball is v1
final velocity of 0.242 kg ball is v2
Now, using conservation of momentum during collision ,
m1 * v1 + m2 * v2 = m1*u1 + m2*u2
0.484 * v1 + 0.242 * v2 = 0.484 * 3.76 -----(1)
as the collision is elastic ,
coefficient of restitution = 1
3.76 = v2 - v1 ----(2)
solving 1 and 2
v1 = 1.25 m/s
v2 = 5.01 m/s
A) the speed of 0.484 kg mass is 1.25 m/s
B) direction of velcity is east direction
c)
speed of 0.242 kg mass is 5.01 m/s after the collision
d)
direction of velocity is east direction
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