Driving home from school one day, you spot a ball rolling out into the street. You brake for 1.20 s, slowing your 950-kg car from 16.0 m/s to 9.50 m/s. (a) What is the average force exerted on your car during breaking? (b) How far did you travel while breaking?
Solution:
a) Using the concept of impulse,
Favgt = mv
Favg = mv/t
= 950*[9.50 - 16]/1.20
= - 5145.83 N.
b) Using kinematics equation,
Find the acceleration,
a = v - u/t
= 9.50 - 16 / 1.2
= -5.42 m/s2.
And finding the distance,
S = v2 - u2/2a
= 9.52 - 162/2*-5.42
= 15.3 m.
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