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How far apart must two charges of 68.68 nC be to have a force of 7.7...

How far apart must two charges of 68.68 nC be to have a force of 7.7 N between them?

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Answer #1

The electrostatic force two charged particles is,

              F = k q2/r2

Here, q is charge on two particles and r is the seperation between the charges.

             r 2 = (9x109 N m2 / C2) (6.68x10-9 C) / 7.7 N

             r   = 2.28x10-4 m

                 = 0.228 mm

                 = 0.23 mm

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