A wire carries a current of 14.0 A in a direction that makes an angle of 31.0
given that current carrying by the wire is i=14.0A
magnetic field strength B=0.300T
angle between i and B is ?=31 degree
length of the wire is l=4.00m
magnetic force F=Bilsin?
=0.300*14.0*4*sin31
=8.653 N
Get Answers For Free
Most questions answered within 1 hours.