There is a potential difference of 1.1 V between the ends of a 10 cm long graphite rod that has a cross-sectional area of 1.3 mm2. The resistivity of graphite is 7.5 10-6 Ω-m.
(a) Find the resistance of the rod.
(b) Find the current.
(c) Find the electric field inside the rod.
Resistance of a wire of length l and area A is given by
is the resistivity of the material
a) Given that,
Putting the values,
b) By Ohm's law, current through the rod is
c) For a potential difference V, over a length l, electric field is given by
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