Question

What is strength of the electric field between two parallel conducting plates separated by 1.00 cm and having an electric potential difference between them of 15,000 V?

A) 1.5 kV/m

B) 15 kV/m

C) 1.5 MV/m

D) 15MV/m

Answer #1

Option ( C) 1.5 Mv/m is Correct.

Electric field strength can be find using below formula

The electric field strength between two parallel conducting
plates separated by 3.00 cm is 7.0 x 10^4 V/m. What is the
potential difference between the plates?
Please include a picture, and show work pls!!! I need to
understand this!!!

Two parallel conducting plates are separated by 10.0 cm, and one
of them is taken to be at zero volts.
(a) What is the magnitude of the electric field strength between
them, if the potential 7.25 cm from the zero volt plate (and 2.75
cm from the other) is 333 V?
_______kV/m
(b) What is the absolute value of the potential difference between
the plates?
_______V

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(B) FInd the total capacitance of the combination of capacitors
(C1 = 0.310 µF, C2 = 22.5
µF.)
(C)585 C passes through a flashlight...

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The surfaces of two large parallel conducting plates separated
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Two 2.40 cm × 2.40 cm plates that form a parallel-plate
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A. What is the electric field strength inside the capacitor if
the spacing between the plates is 1.00 mm ?
B. What is potential difference across the capacitor if the
spacing between the plates is 1.00 mm ?
C. What is the electric field strength inside the capacitor if
the spacing between the plates is 2.00 mm ?
D. What is...

Two 2.20 cm × 2.20 cm plates that form a parallel-plate
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A) What is the electric field strength inside the capacitor if
the spacing between the plates is 1.00 mm ?
B) What is potential difference across the capacitor if the
spacing between the plates is 1.00 mm ?
C) What is the electric field strength inside the capacitor if
the spacing between the plates is 2.00 mm ?
D) What is...

1. What is the energy stored in the 8.1 μF capacitor of a heart
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2. How far apart are two conducting plates that have an electric
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An air-filled capacitor consists of two parallel plates, each
with an area of 7.6 cm2, separated by a distance of 2.20
mm.
(a) If a 18.0 V potential difference is applied to these plates,
calculate the electric field between the plates.
kV/m
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nC/m2
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pF
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pC

An air-filled capacitor consists of two parallel plates, each
with an area of 7.60 cm2, separated by a distance of
1.70 mm. A 15.0-V potential difference is applied to these
plates.
(a) Calculate the electric field between the plates.
kV/m
(b) Calculate the surface charge density.
nC/m2
(c) Calculate the capacitance.
pF
(d) Calculate the charge on each plate.
pC

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