Question

What frequencies (in Hz) will a 1.95 m long tube produce in the audible range (20 Hz - 20,000 Hz) at 15.0°C for the following cases?

(a)

the tube is closed at one end

lowest frequency Hzsecond lowest frequency Hzhighest frequency (rounded to the nearest Hz) Hz

(b)

the tube is open at both ends

lowest frequency Hzsecond lowest frequency Hzhighest frequency (rounded to the nearest Hz) Hz

Answer #1

What frequencies (in Hz) will a 1.55 m long tube produce in the
audible range (20 Hz - 20,000 Hz) at 21.0°C for the following
cases?
the tube is closed at one end
lowest frequency Hzsecond lowest frequency Hzhighest frequency
(rounded to the nearest Hz) Hz
(b)
the tube is open at both ends
lowest frequency Hzsecond lowest frequency Hzhighest frequency
(rounded to the nearest Hz) Hz

You have two air columns that are each 2.470 m long. One column
is open at both ends and the other is closed at one end. You wish
to determine the frequencies you can produce in the audible range
(20 Hz–20,000 Hz) on a day when the temperature of the air is at
24.00°C. (Give your answers to at least four significant figures.
Assume that the speed of sound at 0° C is exactly 331 m/s.)
(a) in the column...

You have two air columns that are each 1.870 m long. One column
is open at both ends and the other is closed at one end. You wish
to determine the frequencies you can produce in the audible range
(20 Hz–20,000 Hz) on a day when the temperature of the air is at
6.000°C. (Give your answers to at least four significant figures.
Assume that the speed of sound at 0° C is exactly 331 m/s.)
(a) in the column...

A pipe is 2.37 m long.
(a) Determine the frequencies of the first three harmonics if
the pipe is open at both ends. Take 344 m/s as the speed of sound
in air.
f1 = 72.6 Correct: Your answer is correct. Hz
f2 = 145.2 Correct: Your answer is correct. Hz
f3 = 217.8 Correct: Your answer is correct. Hz
(b) How many harmonic frequencies of this pipe lie in the
audible range, from 20 Hz to 20000 Hz?
275...

What is the minimum and maximum harmonic (what n numbers) that a
2.75m-long tube will produce in the audible range of human hearing
if: (a) the tube is closed at one end? (b) the tube is open at both
ends?

A musician measures the frequencies of the audible standing
waves in an organ pipe. He finds two adjacent tones at 245 and 315
Hz. (a) On the basis of this discovery, the musician computes the
pipe's fundamental frequency. What is its value (in Hz)? Hz (b) Is
the pipe open at both ends or only one? open at both ends open at
only one end (c) The air within the pipe has a temperature of 20°C
and is at atmospheric...

A tube closed at one end has resonant frequencies that are 300
Hz apart. If this tube is now opened at both ends, what is the 1st
harmonic frequency?
Please explain the n values in great detail used for the
formulas (other Chegg answers do not do this).

4. A pipe 0.45 m long has two consecutive harmonics with
frequencies of 929 Hz and 1300 Hz.
(a) Is the pipe open at both ends or closed at one?
(b) What is the wave speed in the pipe?
(c) What is the temperature of the air?

The shortest pipe in a particular organ is 1.37 m.
(a)
Determine the frequency (in Hz) of the seventh harmonic (at 0°C)
if the pipe is closed at one end.
Hz
(b)
Determine the frequency (in Hz) of the seventh harmonic (at 0°C)
if the pipe is open at both ends.
(c)
Determine these frequencies (in Hz) at 20.0°C.
pipe
frequency (Hz)
closed
open

A soprano saxophone is approximately a conical tube 0.75 m long
that is open at the wide end and closed at the apex. The wide end
is about 8 cm in diameter. Find the frequency of the lowest note
(in Hz) at 20 C. Neglect the end correction at the open end. The
result you find should be higher than the actual lowest note of a
soprano sax, which is A3-flat.

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