A 200-turn rectangular coil having dimensions of 3.0 cm by 6.0 cm is placed in a uniform magnetic field of magnitude 0.76 T. (a) Find the current in the coil if the maximum torque exerted on it by the magnetic field is 0.14 N · m. A (b) Find the magnitude of the torque on the coil when the magnetic field makes an angle of 25° with the normal to the plane of the coil. N · m
here,
number of turns , N = 200 turns
area , A = 3 cm * 6 cm = 18 cm^2 = 18 * 10^-4 m^2
magnetic feild , B = 0.76 T
a)
let the current in the coil be I
maximum torque , Tm = N * I * A * B
0.14 = 200 * I * 18 * 10^-4 * 0.76
solving for I
I = 0.51 A
the current in the coil is 0.51 m
b)
theta = 25 degree
the magnitude of the torque on the coil when the magnetic field makes an angle of 25 degree with the normal to the plane of the coil , T = Tm * sin(theta)
T = 0.14 * sin(25) = 0.059 N.m
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