Question

The specific heat of a 97 g block of material is to be determined. The block is placed in a 25 g copper calorimeter that also holds 60 g of water. The system is initially at 20°C. Then 112 mL of water at 80°C are added to the calorimeter vessel. When thermal equilibrium is attained, the temperature of the water is 54°C. Determine the specific heat of the block.0000000
_______cal/g·K

Answer 1

Heat released by water = mass x specific heat capacity of water x temperature change

= 112 * 1 * (80 - 54) = 2912 cal

Heat absorbed by material = mass x specific heat capacity of material x temperature change

= 97*c * (54 - 20) =3298 c

Heat absorbed by calorimeter = mass * specific heat capacity of Cu x temperature change

= 25 * 0.092 * (54 - 20) = 78.2 cal

Heat absorbed by water = mass x specific heat capacity of water x temperature change

= 60 * 1 * (54 - 20) = 2040 cal

Conservation of energy requires total heat absorbed = total heat released

3298c + 78.2 + 2040 = 2912

c = 0.241 cal/g.K

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