Question

In procedure 1 capacitors in series: Determine the equivalent capacitance assuming: C1 = 107 μF C2 = 269 μF C3 = 407 μF Enter your response to three significant figures in units of μF.

In procedure 2 capacitors in parallel : Determine the equivalent capacitance assuming: C1 = 197 μF C2 = 285 μF C3 = 422 μF Enter your response to three significant figures in units of μF.

Edit: Removed part 3.

Answer #1

**In** **procedure 1 capacitors in series
:**

Here three capacitors are in series,

C1 = 107 uF, C2 = 269 uF, C3 = 407 uF

Now, let equivalent capacitance be C

Now by using formula,

By solving this we get,

C = 64.432 uF

**In procedure 2 capacitors in parallel :**

C1 = 197 uF

C2 = 285 uF

C3 = 422 uF

Now, here capacitors are parallel so equivalent capacitance is C.

And C = C1 + C2 + C3 = (197+285+422 ) uF = 904 uF

In case of any doubt please discuss in comment section below.

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