A rock is dropped from the top of a tall building. The rock's displacement in the last second before it hits the ground is 40 %% of the entire distance it falls. How tall is the building?
Let, Height of building = H
Let, Time taken by rock to reach the ground = T
Given, initial velocity of rock=0
Dispalcement of rock in last second =
We know that displacement covered in last second is given by
also , ----------------1)
So, -------------2)
Dividing 1) and 2)
so, T=4.40s
Putting this value of T in equation 1),we get hieght of building as
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