Question:A negative charge of q =
-3.1 × 10-17C and m = 4.7 × 10-26 kg...
Question
A negative charge of q =
-3.1 × 10-17C and m = 4.7 × 10-26 kg...
A negative charge of q =
-3.1 × 10-17C and m = 4.7 × 10-26 kg
enters a magnetic field B = 0.55 T with initial velocity
v = 230 m/s, as shown in the figure. The magnetic field
points into the screen.
q = -3.1 × 10-17C m = 4.7 × 10-26 kg B = 0.55 T v = 230 m/s
13%
Part (a) Which direction will the magnetic force be on the
charge?
13% Part (b) Express
the magnitude of the magnetic force, F, in terms of
q, v, and B. 13% Part (c) Calculate the magnitude
of the force F, in newtons. 13% Part (d) Under such a magnetic
force, which kind of motion will the charge undergo? 13% Part (e) Express the centripetal
acceleration of the particle in terms of the force F and
the mass m. 13% Part (f) Calculate the magnitude
of a, in meters per square second. 13% Part (g) Express the radius,
R, of the circular motion in terms of the centripetal
acceleration a and the speed v. 13% Part (h) Calculate the numerical
value of the radius R, in meters.