Question

- A 200 keV photon scatters from a free electron. The scattered
photon has 10% less energy than the original photon. (a) Through
what angle has the photon been scattered? (b) What is the kinetic
energy of the scattered electron?{44
^{o}}

Answer #1

A 570-keV gamma ray Compton-scatters from an electron. Find the
energy of the photon scattered at 104°, the kinetic energy of the
scattered electron, and the recoil angle of the electron. E'photon
= keV KE'electron = keV ϕ = °

A 640-keV gamma ray Compton-scatters from an electron. Find the
energy of the photon scattered at 101°, the kinetic energy of the
scattered electron, and the recoil angle of the electron. E'_photon
= ___keV
KE'_electron = ____keV
ϕ = ____ °

A photon scatters off a free electron. The wavelength of the
incident photon is 27.6 ✕ 10−4 nm. The electron recoils
with a kinetic energy that is 0.87 times the energy of the
scattered photon. Determine the scattering angle.

A 110 keV X-ray photon coherently scatters off one of the
valence electrons of a nitrogen atom. Assume that the scattering
angle of the photon is θ = 15°. (Use 511 keV for the
energy of an electron at rest, 1.602 ✕ 10−19 C for the
charge of the electron, and 2.998 ✕ 108 m/s for the
speed of light in vacuum.)
a) Calculate the energy of the scattered photon (in
keV).
b) Calculate the velocity of the ejected electron...

An X-Ray photon with an energy of E = 128 keV undergoes Compton
Scattering at an angle of θ = 33°. What is the wavelength
(λ0) of the incident photon (in nm)? Use h = 4.136 x
10-15 eVs and c = 3 x 108 m/s.
What is the wavelength (λ') of the scattered photon (in nm)?
What is the energy (E’) if the scattered photon (in keV)? Use h
= 4.136 x 10-15 eVs and c = 3 x...

A photon of wavelength 0.04320 nm strikes a free electron and is
scattered at an angle of 37.0 ? from its original direction. Find
the change in energy of the photon. Is the change in energy of the
photon a loss or a gain ? Find the energy gained by the electron.
please do it in eV

Derive an expression for the interaction between a photon
incident on a nearly-free electron in an aluminum target. Make sure
to consider conservation of both relativistic energy and momentum
for the photon and electron before and after the interaction. If an
incident photon has an energy of 662 keV, calculate the energy of
the photon that is scattered through an angle of 35˚.

The maximum characteristic x-ray photon energy comes from the
capture of a free electron into a K shell vacancy. What is this
photon energy in keV for iridium assuming the free electron has no
initial kinetic energy?

A photon of wavelength 4.88 pm scatters at an angle of 102
degrees from an initially stationary, unbound electron. What is the
de Broglie wavelength of the electron after the photon has been
scattered?
de Broglie wavelength: pm

Compton Scattering.A photon of wavelength λcollides elastically
with a free electron (initially at rest) of mass m. If the photon
scatters at an angle φfrom its original direction of travel, use
conservation of relativistic linear momentum and conservation of
relativistic energy to derive a mathematical expression for the
scattered photon’s wavelength λ’.

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