Question

An clown is spinning with an angular momentum of 4kg m^2/s^2. A torque of (7+3t)Nm acts upon the clown for 3 seconds.

What is the clown's final angular momentum?

Answer 1

We know that torque is given by:

Torque = = dL/dt

dL = Change in Angular momentum

Torque = = 7 + 3t

So,

dL = *dt

Using integration

Now given that at t = 0, Angular momentum, L = 4

So,

4 = 7*0 + 3*0 + C

C = 4

After 3 second, final angular momentum will be

L = 7*3 + 3*3^2/2 + 4

L = 38.5 kg-m^2/sec^2

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