Calculate the expected ∆Tb =
T^2_b/λ(2c) when c = 0.05.
The above equation presents the form of Wein's dispalcement law
which states thatone of the relations between the emission
spectrum of a black body and its temperature. It states
that the higher the temperature, the lower the wavelength
λ
max
for which the radiation curve
reaches its maximum. The shift to shorter wavelengths corresponds
to photons of higher energies. In other words,
λ
max
(peak wavelength) is
inversely proportional to temperature.
Accordingly
λ
max
= b / T
where:
λ
max
is the aforementioned peak
wavelength of light,
T
is an absolute temperature of a black body im
kelvin
b = 2.8977729 mm*K
is the Wien's displacement
constant.
Puttting the values in the above equation
λ
max
= 10607 nm
If we consider the above equation and put the values
for
∆Tb =T^2_b/λ(2c)
then T=273.05 K , b=2.8977729*10-3 m*K
∆Tb={(273.05)^(2*2.8977*10-3)2}/(10607*10^-9*2*3*10^8)
=11 mm
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