Question

A projectile of mass m = 5kg is thrown upward vertically with a velocity v0 =...

A projectile of mass m = 5kg is thrown upward vertically with a velocity v0 = 9 m/s

a) Starting with Newton's 2nd Law FNet = ma, calculate the time to an accuracy of four decimal places at which the maximum height is reached when no air resistance is present.

b) Starting with Newton's 2nd Law FNet = ma, calculate the time to an accuracy of four decimal places at which the maximum height is reached when considering the following force of air resistance:

Fair = 7.775 x 10-5v

c) Starting with Newton's 2nd Law FNet = ma, calculate the time to an accuracy of four decimal places at which the maximum height is reached when considering the following force of air resistance:

Fair = 0.055v2

Please Show Work

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A ball of mass m=2.00 kg is thrown vertically with velocity v0=10.0 m/s. a) What maximum...
A ball of mass m=2.00 kg is thrown vertically with velocity v0=10.0 m/s. a) What maximum height would it reach if the average force of air resistance were Fd= 5 N? [4.06 m] b) The ball lands on a spring (with k=200 N/m), which brings it to a stop 1 m above the launch point. How much would the spring compress before the ball stops? (Assume that air resistance acts the entire way) [0.67 m] I don't know how to...
A ball is thrown vertically upward from the edge of a cliff, with an upward velocity...
A ball is thrown vertically upward from the edge of a cliff, with an upward velocity of 20 m/s. On its way back down, it just misses the end of the cliff. (a) Find the position and velocity of the ball 1 s and 4 s after it is thrown; (b) Find the velocity of the ball when it is 5 m above the flat surface of the cliff. Write the magnitude of the velocity in the Answer box below...
URGENT A ball is thrown vertically upward from the edge of a cliff, with an upward...
URGENT A ball is thrown vertically upward from the edge of a cliff, with an upward velocity of 20 m/s. On its way back down, it just misses the end of the cliff. (a) Find the position and velocity of the ball 1 s and 4 s after it is thrown; (b) Find the velocity of the ball when it is 5 m above the flat surface of the cliff. Write the magnitude of the velocity in the Answer box...
A ball with mass 1/9.8 kg is thrown upward with initial velocity 20 m/s from the...
A ball with mass 1/9.8 kg is thrown upward with initial velocity 20 m/s from the roof of a building 30 m high. Assume that the force of air resistance (drag force) is (v^2)/1225. Find the maximum height above the ground that the ball reaches. (Hint: find the velocity v(t) first, then find the height x(t).)
A ball with mass m kg is thrown upward with initial velocity 16 m/s from the...
A ball with mass m kg is thrown upward with initial velocity 16 m/s from the roof of a building 28 m high. Neglect air resistance. Use 9.8 m/s2. Round your answers to one decimal place. (a) Find the maximum height above the ground that the ball reaches. meters (b) Assuming that the ball misses the building on the way down, find the time that it hits the ground.
A ball of mass m is projected vertically upwards at a velocity v◦. The ball experiences...
A ball of mass m is projected vertically upwards at a velocity v◦. The ball experiences an air resistance force (in addition to gravity) of the form FR = −αv^2 where α > 0 is constant and v is the velocity, and reaches a maximum height h before it returns back to the point of projection. (a) Write down the equations of motion of the ball during its upward and and downward journeys and show that the maximum height reached...
A ball is thrown vertically upward from a height of 5 ft with an initial velocity...
A ball is thrown vertically upward from a height of 5 ft with an initial velocity of 83 ft/s. The distance s (in feet) of the ball from the ground after t seconds is s = s(t) = 5 + 83t − 16t^2. (a) What is the velocity v, in feet per second, of the ball after 2 seconds? (b) When, in seconds, will the ball reach its maximum height? (Round your answer to one decimal place.) (c) What is...
2. A rocket blasts off vertically from the launch pad with a constant upward acceleration of...
2. A rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25 m/s^2 and feels no air resistance. When it has reached a height of 525 m, its engines suddenly fail so that the only force acting on it is now gravity. a) How fast is the rocket traveling when the engine fails? b)What is the maximum height the rocket will reach above the launch pad? c) How much time after engine failure will elapse...
An airplane in flight is subject to an air resistance force proportional to the square of...
An airplane in flight is subject to an air resistance force proportional to the square of its speed v. But there is an additional resistive force because the airplane has wings. Air flowing over the wings is pushed down and slightly forward, so from Newton's third law the air exerts a force on the wings and airplane that is up and slightly backwardThe upward force is the lift force that keeps the airplane aloft, and the backward force is called induced drag. At...
For his engineering project, Fran¸cois built a model rocket of mass m = 0.55 kg simply...
For his engineering project, Fran¸cois built a model rocket of mass m = 0.55 kg simply by using materials he found lying around the lab and blueprints he found on the internet. The rocket’s propulsion is provided by a special battery-powered fan that is able to provide a constant force |Ffan| = 7.0 N – that is, once it is launched in a specific direction, the direction of the fan’s force does not change. The downside is that the rocket...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT