Question

**A parallel plate capacitor has plates of area A =0.055
m2 separated by distance d =1.60 ✕ 10−5 m and is attached to a
battery with potential difference ΔV = 22 V.(The permittivity of
free space is εo= 8.85 ✕ 10−12 C2/N·m2).**

- calculate the capacitance in F if the space between the plates is filled with air
- what is the electric field between the plates of the capacitor
- suppose the capacitor is replaced with another capacitance C= 1.90 x10^-5 F, what is the energy stored
- with the same condition from c, the charging battery is now disconnected and a cermamic slab with dielectric constant K=3.10 is slipped between the plates of the new capacitor. What is the energy stored in the capacitor now?

Answer #1

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A parallel plate capacitor has plates of area A =0.055
m2 separated by distance d =2.20 ✕ 10−5 m and
is attached to a battery with potential difference ΔV = 19 V.(The
permittivity of free space is εo= 8.85 ✕
10−12 C2/N·m2).
(a) Calculate the capacitance (in F) if the space between the
plates is filled with air.
(b) What is the electric field between the plates of the
capacitor? In N/C
Suppose that this capacitor is replaced with another...

A parallel plate capacitor has plates of area A =0.075
m2 separated by distance d =2.30 ✕ 10−5 m and
is attached to a battery with potential difference ΔV = 14 V.(The
permittivity of free space is εo= 8.85 ✕
10−12 C2/N·m2).
(a)Calculate the capacitance (in F) if the space between the
plates is filled with air.
(b) What is the electric field between the plates of the
capacitor?
Suppose that this capacitor is replaced with another
with capacitance C...

A parallel plate capacitor has plates of area A =0.075 m2
separated by distance d =1.00 ✕ 10−5 m and is attached to a battery
with potential difference ΔV = 10 V.(The permittivity of free space
is εo= 8.85 ✕ 10−12 C2/N·m2). (a) Calculate the capacitance (in F)
if the space between the plates is filled with air. F (b) What is
the electric field between the plates of the capacitor? Suppose
that this capacitor is replaced with another with...

A parallel-plate capacitor has plates of area 0.16 m2 and a
separation of 1.20 cm. A
battery charges the plates to a potential difference of 180 V and
is then
disconnected. A dielectric slab of thickness 0.4 cm and dielectric
constant K=3 is
then placed symmetrically between the plates.
a) What is the capacitance before the slab is inserted?
b) What is the capacitance with the slab in place?
c) What is the free charge q before the slab is...

A parallel plate capacitor is made from two plates 7 cm^2 in
area, with a plate separation of 3 mm. The capacitor is fully
charged across a 30 V battery, and then disconnected.
How much charge is on the capacitor?
Now material with a dielectric constant of 30 is inserted to
fill the space between the plates, (with the battery disconnected),
What is the charge on the capacitor?
What is the energy stored in the capacitor?
What the field between...

An air-filled parallel-plate capacitor with capacitance
C0 stores charge Q on plates separated by
distance d. The potential difference across the plates is
ΔV0 and the energy stored is PEC,0. If the
capacitor is disconnected from its voltage source and the space
between the plates is then filled with a dielectric of constant k =
2.00, evaluate the ratios
(a) Cnew/C0,
(b) ΔVnew/ ΔV0, and
(c) PEC, new/PEC, 0.

A parallel-plate capacitor is constructed of plates with area
2.5 m2 that are separated by 0.5 mm of air (dielectric constant Ka
= 1:0006). The capacitor is connected to a 9 V battery and fully
charged. The battery is then disconnected, and quartz is inserted
to ll the gap between the plates (dielectric constant Kq = 4:3).
Determine whether the energy density of this capacitor increased or
decreased when the quartz was inserted, and by how much.

A
parallel plate capacitor of area A = 30 cm2 and separation d = 5 mm
is charged by a battery of 60-V
If the air between the plates is replaced by a dielectric of
k= 4, but the battery disconnected before the dielectric
inserted,
1) Find the capacitance of the capacitor.
2) What is the charge on the capacitor?
3) What is the energy stored in the capacitor?
please explain. Thank you

A dielectric-filled parallel-plate capacitor has plate area A =
30.0 cm2 , plate separation d = 7.00 mm and dielectric constant k =
5.00. The capacitor is connected to a battery that creates a
constant voltage V = 10.0 V . Throughout the problem, use ϵ0 =
8.85×10−12 C2/N⋅m2 .
a. The dielectric plate is now slowly pulled out of the
capacitor, which remains connected to the battery. Find the energy
U2 of the capacitor at the moment when the...

A dielectric-filled parallel-plate capacitor has plate area
A = 30.0 cm2 , plate separation d = 8.00 mm and
dielectric constant k = 4.00. The capacitor is connected
to a battery that creates a constant voltage V = 5.00 V .
Throughout the problem, use ϵ0 = 8.85×10−12
C2/N⋅m2 .
Part A- Find the energy U1 of the dielectric-filled
capacitor.
Part B- The dielectric plate is now slowly pulled out of the
capacitor, which remains connected to the battery. Find...

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