A 13 µC charge is located in a 288 N/C electric field. What is the force the charge experiences? (Hint: 1 µC = 10−6C ). Calculate to 4 decimals.
The electrostatic force experienced by a unit test positive charge at a certain point in the space gives the Electricfield at that point.The unit of Electricfield is Newton per coulomb.It is a vector quantity.
Given magnitude of charge is 13C =C
Also given Electricfield is 28
Therefore the electric force experienced by the charge =product of magnitude of charge and electricfield at that point
=N
= N
N
Rounding it to four decimal places gives N
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