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A parallel plate capacitor has plates of area A =0.075 m2 separated by distance d =1.00...

A parallel plate capacitor has plates of area A =0.075 m2 separated by distance d =1.00 ✕ 10−5 m and is attached to a battery with potential difference ΔV = 10 V.(The permittivity of free space is εo= 8.85 ✕ 10−12 C2/N·m2). (a) Calculate the capacitance (in F) if the space between the plates is filled with air. F (b) What is the electric field between the plates of the capacitor? Suppose that this capacitor is replaced with another with capacitance C = 2.30 ✕ 10−5 F. (c) What is the energy stored in the new capacitor? (d) The charging battery is now disconnected and a ceramic slab with dielectric constant κ = 2.30 is slipped between the plates of the new capacitor. What is the energy stored in the capacitor now?

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