Question

Mirror lab

Object distance = measured distance from object/lighted object to center of mirror = p or do

Image distance = measured distance from center of mirror to image/screen = q or di

Focal length calculated using mirror equation:

(1/f) = (1/p) + (1/q) or (1/f) = (1/do) + (1/di)

Magnification: m = -(q/p) or m = -(di/do)

Procedure pp101-102

Part One: CONCAVE MIRROR

a.) p = q = 38 cm

b.) p > q: p = 50 cm, q = 34.1 cm

c.) p < q: p = 35 cm, q = 45 cm

d.) OMIT part d!

Using measured object(p) and image(q) distances, for a, b & c, above, calculate the Focal Lengths and the Magnifications.

Compare via %difference, the focal lengths: fa to fb, fb to fc & fc to fa.

Part Two: CONVEX MIRROR

Omit part two as written and Substitute the following procedure!

Using your car’s passenger side-view mirror, the one labeled “Objects are Closer than they Appear”, look at your image in the mirror and describe it using the following, CIRCLE you choices:

i. Inverted or Upright

ii. Reverted or Correct

iii. Smaller or Larger

iv. Real or Virtual

From your perspective/point of view, where is your image located?

Part Three: GRAPHICAL ANALYSIS

Construct RAY DIAGRAMS for part ONE, b & c

1)What conclusions can be made about the image forming properties of positive or concave mirrors; and negative or convex mirrors.

2)An upright object is placed in front of a concave mirror. The radius of curvature of the mirror is 40cm.                    a)Where should the object be placed in order to obtain an image that is twice as large as the object?                        b)Is the image upright or inverted?

Answer 1