Question

A wheel rotates with a constant angular acceleration of 3.90 rad/s2. Assume the angular speed of...

A wheel rotates with a constant angular acceleration of 3.90 rad/s2. Assume the angular speed of the wheel is 2.05 rad/s at ti = 0.

(a) Through what angle does the wheel rotate between t = 0 and t = 2.00 s? Give your answer in radians and revolutions.
rad?
rev?

(b) What is the angular speed of the wheel at t = 2.00 s?
rad/s?

(c) What angular displacement (in revolutions) results while the angular speed found in part (b) doubles?
rev

Use the values from previous to help work this exercise.

(a) Find the angle through which the wheel rotates between t = 2.00 s and t = 3.80 s.
rad

(b) Find the angular speed when t = 3.80 s.
rad/s

(c) What is the magnitude of the angular speed four revolutions following t = 3.80 s?
rad/s

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Answer #1

The angular acceleration is constant hence, we can use kinematics equation

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