Question

# Two particles, one with charge −2.93×10−6 C and the other with charge 4.39×10−6 C , are...

Two particles, one with charge −2.93×10−6 C and the other with charge 4.39×10−6 C , are 0.0209 m apart. What is the magnitude of the force that one particle exerts on the other?

magnitude of force:

Two new particles with identical positive charge q3 are placed the same 0.0209 m apart. The force between them is measured to be the same as that between the original particles. What is q3 ?

Given,

The charges, q1 = - 2.93 * 10-6 C and q2 = 4.39 * 10-6 C

The distance, r = 0.0209 m

a)

The electrostatic force, Fe = ( k q1q2) / r2

Fe = ( 9 * 109 * 2.93 * 10-6 * 4.39 * 10-6 ) / (0.0209)2

= 265.022 N

b)

Let the charge of a new particle be q3

The distance is, r = 0.0209 m

Fe = ( k q1q2) / r2   ( q1 = q2)

Fe = k (q3)2 / r2

(q3)2 = Fe r2 / k

(q3)2 =  265.022 * (0.0209)2 / 9 * 109

(q3)2  = 1.29 * 10-11 C

q3 = 3.59 * 10-6 C

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