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a right triangle current loop carries of I=4.22A, and in the presence of a constant magnetic...

a right triangle current loop carries of I=4.22A, and in the presence of a constant magnetic field with magnitude B=2.30T directed perpendicular to one edge of the loop. If angle theta=30 degrees and length L=300 mm, what is the total force on the loop?
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Answer #2

The force due to a magetic field on a current carrying wire is given by

FB = BIL sin

where, B = Magnetic field on the wire

I= current carried by the wire

L= length of wire

= angle between B and I

Therefore, we calculate the magnetic force on each wire in the loop and then calculate the net force

answered by: anonymous
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