Question

A thin layer of transparent oil is placed on top of a transparent plate. The oil...

A thin layer of transparent oil is placed on top of a transparent plate. The oil film is then illuminated by white light shining onto the oil's surface, as shown in the figure above. To an observer standing right next to the light source and looking straight down on the oil film, the oil film appears green, corresponding to a wavelength of 528 nm in air. The oil has an index of refraction of 1.52.

Part (A) What is the frequency of this green light in air? Hz

Part (B) What is the frequency of this green light in oil? Hz

Part (C) What is the wavelength of this green light in oil? nm

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Answer #1

A) The frequency of the green light in air corresponding to wavelength of 528 nm in air is given by c = f

=> 3 x 108 m/s = 528 nm x f

=> f = 5.68 x 1014 Hz

B) The frequency of the light remains same even after refraction as the source is same.

C) The wavelength changes in a refractive medium as the speed of light changes in a medium and that it is given by;

n2/n1 = 1/2

=> 2 = n11/n2

as n1 = 1(R.F of air)

n2 = 1.52

1 = 528nm

So, 2 = 347.37 nm

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