Question

Consider the following. (Let C1 = 14.40 µF and C2 = 8.40 µF.) A rectangular circuit contains a battery and four capacitors. The bottom side has a 9.00 V battery with the positive terminal on the left. The left and right sides of the circuit each contain a capacitor labeled C1. The top side splits into two parallel horizontal branches, which recombine before reaching the top right corner. There is a 6.00 µF capacitor on the upper branch and a capacitor labeled C2 on the lower branch.

(a) Find the equivalent capacitance of the capacitors in the figure. µF

(b) Find the charge on each capacitor. on the right 14.40 µF capacitor µC on the left 14.40 µF capacitor µC on the 8.40 µF capacitor µC on the 6.00 µF capacitor µC

(c) Find the potential difference across each capacitor.

on the right 14.40 µF capacitor V

on the left 14.40 µF capacitor V

on the 8.40 µF capacitor V

on the 6.00 µF capacitor

Answer 1