Question

This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The magnitude of the force is different in the two cases, while the directional angle θ is the same. Kinetic friction exists between the block and the wall, and the coefficient of kinetic friction is 0.310. The weight of the block is 47.0 N, and the directional angle for the force F → is θ = 31.0°. Determine the magnitude of F → when the block slides (a) up the wall and (b) down the wall.

Answer #1

(a) Since the force is pushing the block up the wall with a constant velocity, therfore net force on the block in the direction of motion is zero

Forces acting on the block along the wall are-

1. Kinetic Friction, (vertically downward)

(Horizontal component of Force F)

2. Weight ,

3. Vertical component of Force , i.e.

Now, balancing the forces-

(b) In this case friction force will act vertically upward, since the block is sliding down the wall with a constant velocity

A 5.50 kg block is pressed against a vertical wall by a force
(→F), as shown in the figure below. The coefficient of static
friction between the block and the wall is 0.32 and the directional
angle θ for the force is 36.0°. Determine the magnitude of the
force (→F) when the block is about to slide down the wall.

Say you push on a 5 kg block with a force of
Fa = 20 N, at a 45° angle downward. The
coefficient of kinetic friction between the block and the ground is
?k = 0.3. The coefficient of static friction is unknown,
but it is known that ?s > 0.3. The block is moving
with initial velocity to the right (the +x direction),
v0 = 2 m/s.
a) What is the magnitude of the force of friction on the...

Part 1) A 1.0 kg block is pushed 2.0 m at a constant velocity up
a vertical wall by a constant force applied at an angle of 29.0 ◦
with the horizontal, as shown in the figure. The acceleration of
gravity is 9.81 m/s 2. Drawing not to scale. If the coefficient of
kinetic friction between the block and the wall is 0.20, find a)
the work done by the force on the block. Answer in units of J.
Part...

A horizontal force of magnitude F = 100 N is applied to slide a
block of mass m = 5 kg up a ramp inclined at θ = 37 o to the
horizontal. If the coefficient of kinetic friction between the
block and the ramp is 0.4, what will be the acceleration of the
block?

If you push a crate with a force of 80N and it slides at
constant velocity, how great is the friction acting on the
crate?

The three diagrams below show a block of mass m being
pulled or pushed at constant acceleration along a table with a
force F. The coefficient of kinetic friction is
μk. What is the magnitude of the friction force in each
case? Give your answer in terms of the pushing force F,
m, μk, and the angle θ.
case
(i)
fk
=
case
(ii)
fk
=
case
(iii)
fk
=

One end of a horizontal spring with force constant 130.0 N/m N /
m is attached to a vertical wall. A 5.00-kg k g block sitting on
the floor is placed against the spring. The coefficient of kinetic
friction between the block and the floor is μk μ k = 0.400. You
apply a constant force F⃗ F → to the block. F⃗ F → has magnitude
81.0 N N and is directed toward the wall. The spring is compressed...

A block of mass m=5.2kg is acted on by a force
of magnitude F, as shown in the ﬁgure. The force
makes an angle θ=230 with the
horizontal. The coeﬃcients of kinetic and static frictions between
the surface and the block are µk=0.23 and
µs=0.18, respectively. What is F is the
block moves with constant speed?

1. A block of mass is pulled up an incline. F= 34 N, mass= 6kg
and angle= 24 ˚. What is the acceleration of the block if the
coefficient of kinetic friction between the block and incline is
0.12.
2. A 4.0Kg block slides down a 37° incline at a constant speed.
16N force is applied up and parallel to the incline. What is the
coefficient of kinetic friction between the block and the surface
of the incline?

A block of mass m is initially held at rest at point P on an
incline that makes an angle q with respect to horizontal. The
coefficient of kinetic friction between the block and the incline
is mk. After the block slides down the incline from point P, it
starts to slide without friction up a vertical circular track of
radius R. When it reaches the top of the circle, the normal force
(downward) by the track to the block...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 3 minutes ago

asked 3 minutes ago

asked 6 minutes ago

asked 36 minutes ago

asked 45 minutes ago

asked 55 minutes ago

asked 55 minutes ago

asked 56 minutes ago

asked 57 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago