Question

Q1. Electrons are accelerated through a voltage difference of 280 kV inside a high voltage accelerator...

Q1. Electrons are accelerated through a voltage difference of 280 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons?

A. 2.80×105 eV

Q2.What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.)

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Electrons are accelerated through a voltage difference of 235 kV inside a high voltage accelerator tube....
Electrons are accelerated through a voltage difference of 235 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons? 2.35×105 eV What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.)
Electrons are accelerated through a voltage difference of 160 kV inside a high voltage accelerator tube....
Electrons are accelerated through a voltage difference of 160 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons? _____??? What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.) _____???
Electrons are accelerated through a voltage difference of 210 kV inside a high voltage accelerator tube....
Electrons are accelerated through a voltage difference of 210 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons? Tries 0/20 What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.) Tries 0/20
Electrons are accelerated through a potential difference of 940 kV, so that their kinetic energy is...
Electrons are accelerated through a potential difference of 940 kV, so that their kinetic energy is 9.40×105 eV. A) What is the ratio of the speed v of an electron having this energy to the speed of light, c? B) What would the speed be if it were computed from the principles of classical mechanics?
An evacuated tube uses a potential difference of ΔV = 0.58 kV to accelerate electrons, which...
An evacuated tube uses a potential difference of ΔV = 0.58 kV to accelerate electrons, which then hit a copper plate and produce X-rays. Write an expression for the non-relativistic speed of these electrons v in terms of e, ΔV, and m, assuming the electrons start from rest. Calculate the non-relativistic speed of these electrons v in m/s. & The temperature near the center of the Sun is thought to be about 15 million degrees Celsius, that is, 1.5 ×...
In a color television tube, electrons are accelerated through a potential difference of  15500 V. With what...
In a color television tube, electrons are accelerated through a potential difference of  15500 V. With what speed do the electrons strike the screen? Give this speed in terms of the speed of light. Hint: The kinetic energy of an electron which has been accelerated through a potential difference of 1 V has a kinetic energy equal to 1 eV. The Range of answers is between  0.230 and 0.310c I tried to use the conservation principle (1/2 mv2=qv), but that didn't get...
At the 3-km-long Stanford Linear Accelerator, electrons are accelerated to final kinetic energies of 47 GeV....
At the 3-km-long Stanford Linear Accelerator, electrons are accelerated to final kinetic energies of 47 GeV. a. Electrons increase their kinetic energies approximately uniformly every meter as observed in the laboratory frame. What is the energy gain in MeV/m? b. Suppose the classical KE expression was correct – how far along the accelerator tube would the electrons need to travel before they reached light speed? c. OK, but that isn’t really what happens – even at 47 GeV of kinetic...
Q. Electrons are accelerated in a television tube through a potential difference of 9.8 kV. Find...
Q. Electrons are accelerated in a television tube through a potential difference of 9.8 kV. Find the highest frequency and minimum wavelength of the electromagnetic wave emitted, when theses electrons strike the screen of the tube. In which region of the spectrum will these waves lie?   and Q. High energy photons ( y -rays) are scattered from electrons initially at rest. Assume the photons are backscatterred and their energies are much larger than the electron’s rest-mass energy, E >> m0c2...
Electrons are accelerated through a potential difference of 3.59 kV in a cathode ray tube. Calculate...
Electrons are accelerated through a potential difference of 3.59 kV in a cathode ray tube. Calculate the de Broglie wavelength of the electrons.
You wish to build a linear accelerator that will accelerate electrons to 85.9% of the speed...
You wish to build a linear accelerator that will accelerate electrons to 85.9% of the speed of light. You want adjacent drift tubes to be at +5000V and -5000V potentials. To work this problem, you will need the relativistic formula for kinetic energy. (K = mv2/2 doesn't work for really fast particles.) Kinetic energy is K = E0(γ – 1) where E0 is the rest energy of an object. The rest energy of an electron is 0.511 MeV. [Remember that...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT