Question

Jill arranges a selection of uniformly charged rings symmetrically around the x-axis so that the electric...

Jill arranges a selection of uniformly charged rings symmetrically around the x-axis so that the electric potential on the positive x-axis is V(x,0,0) = V0 ln[x/(L+x)], where V0 is in volts and x > 0 . When Jill sketched the arrangement, the z-axis points out of the screen. L and x are in units of meters.

a) Find an expression for the y-component of the electric field, Ey, on the positive x-axis.

b) Find an expression for the z-component of the electric field, Ez, on the positive x-axis.

c) Find an expression for the x-component of the electric field, Ex, on the positive x-axis.

d) Calculate the magnitude of the electric field, in volts per meter, at the observation point (xob = 6.7 m, 0, 0), with xob = 6.7 m, L = 1.25 m, and V0 = 1 V.

Please provide explanations behind your work for my understanding.Thank you very much for your help!

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

we know electric field E= - grad(V) from that relation we can easily find x, y and z component of electric field on + ve x axis.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has...
A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.5 V/m) cos[(π × 1015 s-1)(t - x/c)].(a) What is the amplitude of the magnetic field component?
The electric potential in an electric field is given by V(x, y, z)= (-9.40 V/m5)x3y2 +...
The electric potential in an electric field is given by V(x, y, z)= (-9.40 V/m5)x3y2 + (3.85 V/m4)y4 - (9.8 V/m2)zy. Determine the unit vector form E = [ Ex V/m)i + (Ey V/m)j + (Ez V/m)k] of the electric field at the point whose coordinates are (-1.3 m, 2.3 m, 3.1 m). Give the x, y, z components of electric field in the form "+/-abc" V/m, or, "ab.c" V/m as is appropriate. For example, if you calculate the electric...
The electric component of a beam of polarized light is Ey = (5.27 V/m) sin[(1.03 ×...
The electric component of a beam of polarized light is Ey = (5.27 V/m) sin[(1.03 × 106 m-1)z + ωt]. (a) Write an expression for the magnetic field component of the wave, including a value for ω. What are the (b)wavelength, (c) period, and (d) intensity of this light? (e) Parallel to which axis does the magnetic field oscillate? (f)In which region of the electromagnetic spectrum is this wave?
The electric component of a beam of polarized light is Ey = (5.31 V/m) sin[(1.29 ×...
The electric component of a beam of polarized light is Ey = (5.31 V/m) sin[(1.29 × 106 m-1)z + ωt]. (a) Write an expression for the magnetic field component of the wave, including a value for ω. What are the (b) wavelength, (c) period, and (d) intensity of this light? (e) Parallel to which axis does the magnetic field oscillate? (f) In which region of the electromagnetic spectrum is this wave?
A particle with positive charge q = 4.49 10-18 C moves with a velocity v =...
A particle with positive charge q = 4.49 10-18 C moves with a velocity v = (3î + 5ĵ − k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (5î + 2ĵ + k) T and E = (5î − ĵ − 2k) V/m. (Give your answers in N for each component.) Fx = N Fy = N Fz =...
(a) Write down the equations that relate: (i) The ?− component of the electric field at...
(a) Write down the equations that relate: (i) The ?− component of the electric field at a point specified by position vector ? to the to the electric potential ?(?) at that point. (ii) The ?− component of the electrostatic force acting on a particle of charge ? to the ?− component of the electric field at the position of the particle. And hence deduce an expression for: (iii) The ?− component of the electrostatic force acting on a particle...
A positive electric charge Qis spread out uniformly along a wire of length Lplaced on the...
A positive electric charge Qis spread out uniformly along a wire of length Lplaced on the x-axis, with one end of the wire located at x=-L/2and the other at x=+L/2. Today we are going to find the electric field E=Exi+Eyjlocated at x=0,y=-adirectly below the midpoint of the wire. We will again use the idea of superposition: the total electric field at the point x=0,y=-a is due to the sum of the small electric fields produced by each piece of the...
An electron is located on the x ‑axis at x 0 = − 2.51 × 10...
An electron is located on the x ‑axis at x 0 = − 2.51 × 10 − 6 m . Find the magnitude and direction of the electric field at x = 4.55 × 10 − 6 m on the x ‑axis due to this electron. N / C direction: negative x ‑direction positive x ‑direction neither of these
An infinitely large positively charged nonconducting sheet 1 has uniform surface charge density σ1 = +130...
An infinitely large positively charged nonconducting sheet 1 has uniform surface charge density σ1 = +130 nC/m2 and is located in the xz plane of a Cartesian coordinate system. An infinitely large positively charged nonconducting sheet 2 has uniform surface charge density σ2 = +90.0 nC/m2 and intersects the xz plane at the z axis, making an angle θ = 30∘ with sheet 1. Part A Determine the expression for the electric field in the region between the sheets for...
3. A line is uniformly charged with positive charge. This line of charge has a constant...
3. A line is uniformly charged with positive charge. This line of charge has a constant linear charge density of 84 C/m and extends along the positive y axis from 0 to L=8 cm. The electric field at position a=2 cm along the positive x axis makes an angle with it. Calculate such an angle (in degrees). (Coulomb’s constant k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2).
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT