Question

What will be the equilibrium temperature when a 243 g block of copper at 263 ∘C is placed in a 143 g aluminum calorimeter cup containing 808 g of water at 14.4 ∘C?

Answer 1

Suppose the final temperature is T.

Now Using energy conservation:

Heat gained by water and calorimeter = Heat released by copper

Q1 + Q2 = Q3

m1*C1*dT1 + m2*C2*dT2 = m3*C3*dT3

dT1 = Tf - Ti = T - 14.4

dT2 = T - 14.4

dT3 = 263 - T

m1 = mass of water = 0.808 kg

m2 = mass of calorimeter = 0.143 kg

m3 = mass of copper = 0.243 kg

Now using given values:

0.808*4186*(T - 14.4) + 0.143*900*(T - 14.4) = 0.243*390*(263 - T)

Now Solving above equation

T = (0.808*4186*14.4 + 0.143*900*14.4 + 0.243*390*263)/(0.808*4186 + 0.143*900 + 0.243*390)

T = 20.93 C

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answered by: anonymous