Question

A 2.0 ⁢kg toaster is subjected to one force only. The force is in the positive x direction, and it varies in time such that before t=0.0 s , F=0N; between t=0.0 s and t=3.0 s, F=10N; and after t=3.0 s, the force is 0 N again. If the toaster started from rest, how fast will it be moving at t=5.0 s?

Answer 1

using impulse momentum theorem

change in momentum = Force * time

m(v-u) = F*t

where m is the mass

v is the final velocity

u is the initial velocity

F is the applied force

t is the time for which force is applied

substituting the given values in above formula,

2(v-0) = 10*3

2v = 30

v = 15 m/s

therefore, speed of toaster at t = 5 seconds = 15 m/s

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