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A 1100-kg car sits at rest at the bottom of a 15 degree hill. The driver...

A 1100-kg car sits at rest at the bottom of a 15 degree hill. The driver initiates the accelerator and the engine pushes it up a 15 degree hill with a net force of 4500 N parallel to the hill. There is an effective 0.1 coefficient of kinetic friction. Use energy concepts to calculate the speed of the car after it has moved 40 m along the hill’s surface.

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Answer #2

Let the speed of the car after moved 40 m along the hill's surface is v.

The mass of the car m=1100 kg.

The net force acting on the car is F=4500 N.

The coefficient of kinetic friction is 0.1.

Let the height of the hill's top is h.

From the concept of the conservation of the energy, we can say

  

  

  

The speed of the car after moved 40 m along the hill's surface is 14.14521759 m/s or 14.15 m/s approximately.

answered by: anonymous
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