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In a Rutherford scattering experiment, an α-particle (charge = +2e) heads directly toward a lead nucleus...

In a Rutherford scattering experiment, an α-particle (charge = +2e) heads directly toward a lead nucleus (charge = +82e). The α-particle had a kinetic energy of 4.5 MeV when very far (r → ∞) from the nucleus. Assuming the lead nucleus to be fixed in space, determine the distance of closest approach (in fm). Hint: Use conservation of energy with PE = keq1q2 r .

answer in ______ fm

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