Question

A 10 g bullet is fired at 394.5 m/s into a solid cylinder of mass 22.1 kg and a radius 0.57 m. The cylinder is initially at rest and is mounted on fixed vertical axis that runs through it's center of mass. The line of motion of the bullet is perpendicular to the axle and at a distance 8.3 cm from the center. What is the initial angular momentum of the system?

Answer 1

the bullet has angular momentum with respect to the cylinder; the amount of this angular momentum is m v d where m is the bullet mass, v is its velocity and d is its perpendicular distance from the cylinder's rotation axis.

SInce, cylinder is at rest its angular momentum will be zero.

L_i = m v d   

So, initial angular momentum = (0.010 kg)(394.5 m/s)(0.083 m) = 0.327 kgm²/s

and, according to law of conservation of angular momentum, angular momentum of system after collision will also be same.

answered by: anonymous