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Coulomb's law for the magnitude of the force F between two particles with charges  Q and  Q′ separated...

Coulomb's law for the magnitude of the force F between two particles with charges  Q and  Q′ separated by a distance d is

|F|=K|QQ′|d2,

where K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q1 = -14.5 nC , is located at x1 = -1.655 m ; the second charge, q2 = 33.5 nC , is at the origin (x=0.0000).

What is the net force exerted by these two charges on a third charge q3 = 50.5 nC placed between q1 and q2 at x3 = -1.145 m ?

Your answer may be positive or negative, depending on the direction of the force.

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