Question

The systems shown below are in equilibrium with m = 2.50 kg and ? = 34.0

Answer 1

2 masses of 2.5 kg:
2(2.5 kg) = 5.00 kg

By looking at and analyzing the position of the masses in the diagram, the universal g constant, 9.81 m/s^2, must be divided by 2 and multiplied by the total kg:
(9.81 m/s^2) / 2 = 4.905 m/s^2
4.905 m/s^2(5.00 kg) = 24.525 kg(m/s^2) = 24.525 N


(b)
Since there are 2 masses:
2(2.5 kg) = 5.00 kg

Now to get the answer, multiply the total kg by the universal g constant, 9.81 m/s^2 because the force is acting downwards:
5.00 kg(9.81 m/s^2) = 49.05 kg(m/s^2) = 49.05 N

(c)
On an incline, you must take into account the x and y components of the force acting on the block. Therefore, take the cosine of 34 degrees:
cos(34 degrees) = 0.829

Multiply the cos(34 degrees) by 2.5 kg and g:
2.5 kg(0.829)(9.81 m/s^2) = 20.332 kg(m/s^2) = 20.332 N