Question

- A Li
^{2+}ion undergoes a transition from the*n*= 4 to the*n*= 3 state. What is the energy of the emitted photon? - What is the ground state configuration of chlorine (
*Z*= 17)?

- The energy gap for a semiconductor is 1.25 eV. Of the frequencies given below, what is the minimum frequency photon than can move an electron from the valence band to the conduction band?
- An LED emits light of wavelength 600 nm. What is its band gap?

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Answer #1

A singly-ionized lithium ion Li2+ de-excites from a n= 4 state
to a n= 2 state.
What is the energy of photon emitted during this process?

The ground-state energy of a harmonic oscillator is 6 eV.
If the oscillator undergoes a transition from its n=3 to n=2 level
by emitting a photon, what is the energy (in eV) of the emitted
photon?

An electron in He+ undergoes a transition from n = 4 to n = 2
state. Calculate the (a) energy in J, (b) frequency in Hz, (c)
wavelength in nm and (d) wave number in cm-1 of the photon
emitted.

The occupancy probability function can be applied to
semiconductors as well as to metals. In semiconductors the Fermi
energy is close to the midpoint of the gap between the valence band
and the conduction band. Consider a semiconductor with an energy
gap of 0.88 eV, at T = 320 K. What is the probability that (a) a
state at the bottom of the conduction band is occupied and (b) a
state at the top of the valence band is not...

Calculate the wavelength of a photon emitted when the electron
in a Li2+ ion relaxes from the n=8 energy level to the n=4 energy
level. (Use Bohr's model of the atom.)

The occupancy probability function can be applied to
semiconductors as well as to metals. In semiconductors the Fermi
energy is close to the midpoint of the gap between the valence band
and the conduction band. Consider a semiconductor with an energy
gap of 0.66 eV at T 310 K. What is the probability that (a) a state
at the bottom of the conduction band is occupied and (b) a state at
the top of the valence band is not occupied?...

A light-emitting diode (LED) is a semiconductor device (p-n
junction diode) that emits light when an electric current is passed
through it. LEDs are becoming the most popular light sources
because they are much more energy efficient than conventional
incandescent light sources. While the "white" light produced by a
light bulb or the sun is a blend of many different colors, and
these sources typically produce a large amount of heat, LEDs
release only one particular color of light, and...

Consider the electronic transition from n = 4 to n = 1 in a
hydrogen atom, and select the correct statement below: A photon of
97 nm wavelength and 2.05x10-18 J energy was emitted from the
hydrogen atom in this electronic transition. A photon of 97 nm
wavelength and 2.05x10-18 J energy was absorbed by the hydrogen
atom in this electronic transition. A photon of 122 nm wavelength
and 1.64x10-18 J energy was emitted from the hydrogen atom in this...

(1)
Part A: If a electron in a hydrogen atom makes a transition from
ground state to n = 8 level what wavelength of light in (nm) would
be needed for the abosorbed photon to cause the transition?
Part B: If the same electron falls to a lower level by emmitting
a photon of light in the Paschen series what is the frequncy of
light in (Hz) thats emitted?
(2) When a photon have a wavelength of 195nm strikes the...

An electron in a hydrogen atom undergoes a transition from the n
= 6 level to some lower energy level. In doing so, energy is
released in the form of light. a) Calculate the frequency in s-1
(to 3 significant figures) of a photon of light associated with the
highest frequency transition (i.e. largest difference in frequency)
possible from the n = 6 to a lower level. (HINT: Try drawing a
picture first…) b) Calculate the wavelength (in nm) of...

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