Question

The dome of a Van de Graaff generator re- ceives a charge of 1.9 × 10−4 C. The radius of the dome is 5.0 m. Find the magnitude of the elec- tric field strength inside the dome. The value of the Coulomb constant is 8.98755×10 N·m /C . Answer in units of N/C. Find the magnitude of the electric field strength at the surface of the dome. Answer in units of N/C. Find the magnitude of the electric field strength at a distance of 10 m from the center of the dome. Answer in units of N/C.

Please circle each answer

Answer 1

1.

Since, Van de Graaff generator is a conducting sphere.

So, all charge will distribute uniformly on it's surface.

So, Electric field inside a conductor sphere is always zero.

E = 0 N/C

2.

Electric field at the surface of conducting sphere is given by:

E = k*Q/R^2

Q = Charge on sphere = 1.9*10^-4 C

R = radius of sphere = 5.0 m

So,

E = 8.98755*10^9*1.9*10^-4/5.0^2

E = 68305.38 N/ C = 6.83*10^4 N/C

Part C.

Electric field outside the conducting sphere is given by:

E = k*Q/r^2

r = distance from center of sphere = 10 m

So,

E = 8.98755*10^9*1.9*10^-4/10.0^2

E = 17076.345 N/ C = 1.71*10^4 N/C

Let me know if you've any query.

answered by: anonymous