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A bullet of mass 0.0325 kg is fired toward board with a thickness of 0.0335 m....

A bullet of mass 0.0325 kg is fired toward board with a thickness of 0.0335 m. Its speed is 402 m/s before making contact with the board and it passes through the board. The average force exerted on the bullet by the board has a magnitude of 707 N.

What is the speed of the bullet, in m/s, after passing through the board? (The weight of the bullet is negligible relative to the force exerted by the board. Assume the force exerted by the board is constant.)
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Answer #1

Mass of the bullet = m = 0.0325 kg

Initial speed of the bullet = V1 = 402 m/s

Speed of the bullet after passing through the board = V2

Thickness of the board = L = 0.0335 m

Average force exerted on the bullet by the board = F = -707 N (Negative as it opposes the motion of the bullet)

Acceleration of the bullet while passing through the board = a

a = -21753.85 m/s2

V2 = 400.2 m/s

Speed of the bullet after passing through the board = 400.2 m/s

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