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What is the force on the charge located at x = 16.0 cm in the figure...

What is the force on the charge located at x = 16.0 cm in the figure below given that q = 2.25 ?C? The other two charges are located at 6.00 cm and 22.00 cm. Take the positive direction as pointing to the right.

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Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.

What is the force on the charge located at x = 16.0 cm in the figure below given that q = 2.05 ?C? The other two charges are located at 6.00 cm and 22.00 cm. Take the positive direction as pointing to the right.

fore net of -2q = Fon it due to +q at 0.1 m + force on it due to +q at 0.06m

Fnet = Kq(-2q)/0.1^2 + Kq(-2q)/0.06^2

Fnet = 9e9 * -2* 2.05uC * 2.05uC *(1/0.1^2 + 1/0.06^2)

Fnet = 28.577 N

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