Two point charges are located on the x-axis. One has a charge of 1.85 ?C and is located at x = 0.0 m, and the other has a charge of -3.95 ?C and is located at x = 16.9 m. At what location on the x-axis (other than at infinity) would the electric force on a third point charge of 3.32 ?C be zero?
Since Q1= 1.85 ?C and Q2= -3.95 ?C are
opposite in sign there is no place between them where the force
would be zero
Since Q2>Q1 the only point where the force
will be zero is to the left of Q1
Now we find the point where the net electric filed is zero.
Let x be the distance from Q1 and x + 16.9 is the
distance from Q2
Using E = k*q/r2
k*Q1/x2 = k*Q2/(x + 16.9)2
1.85 ?C/x2 = 3.95 ?C/(x + 16.9)2
Rearranging , we get 0.46= x2/(x + 16.9)2
0.68=x/(x + 16.9)
0.68(x + 16.9)=x
0.68x+11.57=x
11.57= x-0.68x
11.57= 0.32x
x= 36.16 m
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