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A charge q1 = 1.62

A charge q1 = 1.62

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Answer #1

a)given the distance of A from q1 is 3d/4. so the distance of A from q2 is d- 3d/4 = d/4

therefore the potentiaal at A is V = 1/40 [ 1.62 x 10-6 / (3d/4) - 5.97x10-6/ (d/4)]

calculating we get V = 173.27 x 103 volt         b) let the distance of q be X from A, then the distance of A from B will be d-X

THE ELECTRIC POTENTIAL WILL BE ZERO WHEN

the potential at A due to q = potential at A due to q

1/40 q1 / X = 1/40 q2 / d-X

Evaluating the expression for X we get X = 1.13 q1 /(q1+q2) where d =1.13m

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