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Three charged particles are at the corners of an equilateral triangle as shown in the figure...

Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 4.00

Homework Answers

Answer #1

a) You have to break the E-fields into components.

Let q1 be 4 microcoulombs and q2 be 7 microcoulombs. The variables will be positive. I'll deal with the negative charge on q1 "by hand".

E-field1 = k (q1) / L^2.
Because q1 is negative, the E-field's direction at q is to the right (positive i-hat), toward q1.

E-field2 = k(q2) / L^2
Because q2 is positive, the field direction at q is left and down, away from q2.
(-cos(60) i-hat - sin(60) j-hat)

Multiply that out.
You've got the vertical component: - sin (60) k(q2) / L^2

You have to subtract the horizontal component of the second E-field from the first: (q1 - q2 cos(60)) k / L^2

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