1/ If three 10 Watt light bulbs are connected in series to a 60V
power supply, what is the current throught each bulb?
resistance of a 10 Watt = v2/p = 602/10 =360
ohm
If three 10 Watt light bulbs are connected in series then
resistance = 3* 360 ohm = 1080 ohm
then current though these bulbs = 60/1080 = 0.0556
A
2/ If a 4th 10 Watt bulb is added in series, would each bulb
burn brighter , dimmer, or remain in the same as before the bulb
was added, and why?[Hint: consider what would happen to the
current.]
If a 4th 10 Watt bulb is added in series, then current through the
bulbs = 60/(4*360) = 0.0416 A
and voltage across the bulb = 60/4 =15V
power of the bulb = 15*0.0416 = 0.625 W
power of a bulb when there were 3 bulbs connected = (60/3)*0.0556 =
1.11 W
so In newly connected circuit each bulb burn
dimmer
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