Question

A uniform electric field has magnitude E and is directed in the negative x direction. The potential difference between point a (at x= 0.70m ) and point b (at x= 0.95m ) is 300V.

Part A

Which point, a or b, is at the higher potential?

Part B

Calculate the value of E.

Express your answer using two significant figures.

Part C

A negative point charge q=?0.200?C is moved from b to a. Calculate the work done on the point charge by the electric field.

Express your answer using two significant figures.

Answer 1

PART-A

electric field is towards our left.

So, for the first query,

B will be at higher potential than A.

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PART-B

E = V/d

E= 300/(0.95-0.70)

E= 1200 V/m

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PART-C

Third, p d 300 V means that work done in taking 1 Coulomb charge is 300 joule

So in taking 0.20 x 10^-6 C the work, of course, done by electric field

W= 300*0.2 *10^-6 joule

W= 6*10^-5 J

W = 60 micro joule.

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