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An electron in a cathode-ray-tube (CRT) accelerates uniformly from 2.00 ? 104 m/s to 6.00 ?...

An electron in a cathode-ray-tube (CRT) accelerates uniformly from 2.00 ? 104 m/s to 6.00 ? 106 m/s over 1.00 cm. (a) In what time interval does the electron travel this 1.00 cm?
(b) What is its acceleration?

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Answer #1

Acceleration of the electron is (a) =v2-u2/2s =(600*104)2 -(2*104)2/2*0.01 =1.79*1015m/s2

Now the time period is given by v=u+at

Then time interval does the electron travel is t =v-u/a =598*104/1.79*1015m

                                                                                   =334.07*10-11s or 3.34*10-9s =3.34nanoseconds

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