1.0kg of water is heated from 0?C to 100?C. Estimate the change in entropy of the water.
Heat absorbed by water in temperature rise, dQ=mC dT
Change in entropy=dQ/T
=mC dT/T
=mC ln(T2/T1)
Here, m=1000g
C=4.184 J/g.?
dS=1000*4.184*ln[(273+100)/273]
=1305.8 J/K
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